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Please find question and answer in the attach file. I just want to check if im correct. Ive solved it using StatCrunch. A researcher wishes to determine if the college students with a “B” average have attain more flying hours by the end of their first semester of college than those that do not have a “B” average at the end of the first semester. The researcher surveys 20 college students that are also student pilots and records their flight hours as well as their GPA (noted as “below B” and “B or better”), and, fortunately, there is an equal number “below B” and “B or better.” The expectation is that those students with a B average or survey results:” better will have more flying hours by the end of their first semester than those students that are below a “B” average. Here are the Below B flying hours B or Better flying hoursa 430 520 410 32 310 44a 360 580 390 510 37 36 140 410 550 45 410 520 Conduct a t test using the five-step hypothesis testing process and StatCrunch. Show your work. 1 1. – Restate the research problem as alternate andnull hypothesis. Ho:u .0.There is no difference that students with a B average or better will have more flying hours at the end of their first semester than those students that are below a B average. 1 Ha: H > 0.There is difference that students with a B average or better will have more flying hours at the end of their first semester than those students that are below a B average. 1 2. – Define the characteristics of the comparison distribution 1 Summary statistics:” Summary statistics: Columna n Mean Std. dev. Mediana B.or Better flying hours 10 48 10.530379 51.50 Below.B-flying hoursa 10 394.0824829 40 3. – Identify the critical score on the comparison distribution. Test the null hypothesis with significance level of 0.05.1 4. + Calculate your observed score and plot it on the comparison distribution. Two sample.T-hypothesis test: 1 HI: Mean of B or Better flying hours 12″: Mean of Below.B flying hours HI-H2: Difference between two means HA: HI-122 0~ (with pooled variances)< Hypothesis testresults: Difference Sample Diff. Std. Err. DF T-State P-valuea 93.5714921 182.5199552 0.0107 5. – Conclude whether to reject or fail to reject the null hypothesis. 1 Since our p-value=0.0107 <0.05 of significance, we reject the null hypothesis. Math Statistics and Probability STATISTICS RSCH 665